What is the standard cell potential for the cell formed by H+ / H2 (E° = 0.00 V) and O2 / H2O (E° = +1.23 V)?

Prepare for the Electrochemistry Test with our extensive quiz. Utilize flashcards and multiple-choice questions with detailed hints and explanations to excel in your exam!

Multiple Choice

What is the standard cell potential for the cell formed by H+ / H2 (E° = 0.00 V) and O2 / H2O (E° = +1.23 V)?

Explanation:
The standard cell potential comes from the difference between the reduction potentials of the two half-reactions, with the higher value acting as the cathode (reduction) and the lower as the anode (oxidation). Here, the O2/H2O couple has a reduction potential of +1.23 V, while the H+/H2 couple is 0.00 V. Since +1.23 V is more positive, oxygen is reduced at the cathode and hydrogen is oxidized at the anode. Therefore, E°cell = E°red(cathode) − E°red(anode) = 1.23 V − 0.00 V = +1.23 V. A positive value means the reaction is spontaneous under standard conditions. The overall reaction is 2H2 + O2 → 2H2O.

The standard cell potential comes from the difference between the reduction potentials of the two half-reactions, with the higher value acting as the cathode (reduction) and the lower as the anode (oxidation). Here, the O2/H2O couple has a reduction potential of +1.23 V, while the H+/H2 couple is 0.00 V. Since +1.23 V is more positive, oxygen is reduced at the cathode and hydrogen is oxidized at the anode.

Therefore, E°cell = E°red(cathode) − E°red(anode) = 1.23 V − 0.00 V = +1.23 V. A positive value means the reaction is spontaneous under standard conditions. The overall reaction is 2H2 + O2 → 2H2O.

Subscribe

Get the latest from Passetra

You can unsubscribe at any time. Read our privacy policy